MCQ
The minimum orbital angular momentum of the electron in a hydrogen atom is:
  • A
    $\text{h}$
  • B
    $\frac{\text{h}}{2}$
  • C
    $\frac{\text{h}}{2\pi}$
  • D
    $\frac{\text{h}}{\lambda}$

Answer

  1. $\frac{\text{h}}{2\pi}$

Explanation:

According to Bohr's atomic theory, the orbital angular momentum of an electron is an integral multiplt of $\frac{\text{h}}{2\pi}$

$\therefore\ \text{L}_\text{n}=\frac{\text{nh}}{2\pi}$

Here,

n = Principal quantum number

The minimum of n is 1

Thus, the minimum value of the orbit angular momentum of the electron in a hydrogen is given by $\text{L}=\frac{\text{h}}{2\pi}$ 

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