The minimum value of $3\cos\text{x}+4\sin\text{x}+8$ is:
- 5
- 9
- 7
- 3
The minimum value of $3\cos\text{x}+4\sin\text{x}+8$ is:
Solution:
The given expression is $3\cos\text{x}+4\sin\text{x}+8$
Let $\text{y}=3\cos\text{x}+4\sin\text{x}+8$
$\Rightarrow\text{y}-8=3\cos\text{x}+4\sin\text{x}$
Minimum value of $\text{y}-8=-\sqrt{(3)^2+(4)^2}$
$\Rightarrow\text{y}-8=-\sqrt{9+16}=-5$
$\Rightarrow\text{y}=8-5=3$
so, the minimum value of the given expression is 3.
Hence, the correct option is (d).
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
A single letter is selected at random from the word ‘PROBABILITY’. The probability that it is a vowel is:
$\frac{1}{3}$
$\frac{4}{11}$
$\frac{2}{11}$
$\frac{3}{11}$
What is the probability of getting the number 6 at least once in a regular die if it can roll it 6 times?
Choose the correct answer.
If $\text{P}(\text{A}\cup\text{B})=\text{P}(\text{A}\cap\text{B})$ for any two events A and B, then:
Let $\text{f(x)}=\sqrt{1+\text{x}^2}$ then.
$\text{f(xy)} = \text{f(x)}.\text{f(y)}$
$\text{f(xy)} \geq \text{f(x)}.\text{f(y)}$
$\text{f(xy)} \leq \text{f(x)}.\text{f(y)}$
None of these