MCQ
The mixed anhydride of nitrogen is
- A$N_2O_2(2NO)$
- ✓$N_2O_4 (2NO_2)$
- C$N_2O_5$
- D$N_2O_3$
✓
Answer
Correct option: B.
$N_2O_4 (2NO_2)$
b
$NO _2$ is called as a mixed anhydride of nitrogen because it gives a mixture of $HNO _2$ and $HNO _3$. Hence option $(B)$ is correct.
$NO _2$ is called as a mixed anhydride of nitrogen because it gives a mixture of $HNO _2$ and $HNO _3$. Hence option $(B)$ is correct.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Amylopectin is a polymer of
Which of the following curves is in accordance with Freundlich adsorption isotherm?
Which one of the following statements is correct
What is the most common type of electrometallurgical processes to obtain pure metal?
For the reaction taking place on water, the order of reaction is
→${{H}_{2}}+C{{l}_{2}}\xrightarrow{\text{Sunlight}}2HCl$
A greenish yellow gas reacts with an alkali metal hydroxide to form a halate which can be preferentially used in fire works and safety matches, the gas and halate respectively are
The given Reaction is
$CCl_3CHO$ $\xrightarrow[KOH]{Conc.}$ Main product is
→For the cell at $298\ K$
→$Ag\left( s \right)\left| {AgBr\left( s \right)\,\left| {B{r^ - }\left( {0.01\,M} \right)} \right|\,\left| {{I^ - }\left( {0.02\,M} \right)} \right|\,AgI\left( s \right)} \right|Ag\left( s \right)$
the correct information is
[Given : $K_{sp}\,\left( {AgBr} \right) = 4 \times {10^{ - 13}}$ ,
$K_{sp}\,\left( {AgI} \right)$ $ = 8 \times {10^{ - 17}},\frac{{2.303\,RT}}{F} = 0.06\,V,\,\log \,2 = 0.3]$
What is final product $(IV)$ in the sequence of $\begin{matrix}
C{{H}_{3}}-CH-OH\xrightarrow{PB{{r}_{3}}}I\xrightarrow{Mg/ether} \\
\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}$ $II\,\xrightarrow{{\begin{array}{*{20}{c}}
{C{H_2} - C{H_2}} \\
\begin{subarray}{l}
\backslash / \\
O
\end{subarray}
\end{array}}}III\,\xrightarrow{{{H_2}O}}IV$
→C{{H}_{3}}-CH-OH\xrightarrow{PB{{r}_{3}}}I\xrightarrow{Mg/ether} \\
\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}$ $II\,\xrightarrow{{\begin{array}{*{20}{c}}
{C{H_2} - C{H_2}} \\
\begin{subarray}{l}
\backslash / \\
O
\end{subarray}
\end{array}}}III\,\xrightarrow{{{H_2}O}}IV$