The mutual characteristic curves of a triode are as shown in figure. The cut off voltage for the triode is
A$0 V$
B$2 V$
C$-4 V$
D$6 V$
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C$-4 V$
From the graph it is clear that of for $V_g=-4 V, i_p=0$, so cut off voltage is $-4$ volt.
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While a collector to emitter voltage is constant in a transistor, the collector current changes by $8.2 mA$ when the emitter current changes by $8.3 mA$. The value of forward current ratio $h$ is