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JEE physics
MCQ
CBSE - English Medium
The ripple factor in a half wave rectifier is
A
$1.21$
B
$ 0.48$
C
$0.6$
D
None of these
[RPMT 2002]
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Solution
A
$1.21$
Ripple factor $r=\sqrt{\left(\frac{I_{m m s}}{I_{d c}}\right)^2-1}$
$=\sqrt{\frac{\left(I_0 / 2\right)^2}{\left(I_0 / \pi\right)^2}-1}=1.21$.
STD 12 Science
JEE physics
Electronics
NCERT
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