MCQ
The number of atoms in $0.1\ mol $ of a triatomic gas is $(N_A = 6.02 \times 10^{23}\, mol^{-1})$
  • A
    $6.026 \times 10^{22}$
  • $1.806 \times  10^{23}$
  • C
    $3.600 \times  10^{23}$
  • D
    $1.800 \times 10^{22}$

Answer

Correct option: B.
$1.806 \times  10^{23}$
b
No. of atoms $=\mathrm{N}_{\mathrm{A}} \times \mathrm{No}$. of moles $\times 3$

$=6.023 \times 10^{23} \times 0.1 \times 3=1.806 \times 10^{23}$

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