MCQ
The number of atoms in $0.1\ mol $ of a triatomic gas is $(N_A = 6.02 \times 10^{23}\, mol^{-1})$
- A$6.026 \times 10^{22}$
- ✓$1.806 \times 10^{23}$
- C$3.600 \times 10^{23}$
- D$1.800 \times 10^{22}$
$=6.023 \times 10^{23} \times 0.1 \times 3=1.806 \times 10^{23}$
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