MCQ
The number of beats produced per second by two vibrations: $x_1 =x_0$ sin $646\pi t$ and $x_2 = x_0 sin 652 \pi t$ is
  • A
    $2$
  • $3$
  • C
    $4$
  • D
    $6$

Answer

Correct option: B.
$3$
b
(b) From the given equation ${\omega _1} = 2\pi {n_1} = 646\pi $==>${n_1} = 323$

and ${\omega _2} = 2\pi {n_2} = 652\pi $ ==> ${n_2} = 326$

Hence, beat frequency $ = 326 - 326 = 3$

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