MCQ
The number of beats produced per second by two vibrations: $x_1 =x_0$ sin $646\pi t$ and $x_2 = x_0 sin 652 \pi t$ is
- A$2$
- ✓$3$
- C$4$
- D$6$
and ${\omega _2} = 2\pi {n_2} = 652\pi $ ==> ${n_2} = 326$
Hence, beat frequency $ = 326 - 326 = 3$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

