MCQ
The number of electrons in $1.6\, C$ charge will be
- ✓${10^{19}}$
- B${10^{20}}$
- C$1.1 \times {10^{19}}$
- D$1.1 \times {10^{2}}$
✓
Answer
Correct option: A.
${10^{19}}$
a
(a) $n = \frac{q}{e} = \frac{{1.6}}{{1.6 \times {{10}^{ - 19}}}} = {10^{19}}$
(a) $n = \frac{q}{e} = \frac{{1.6}}{{1.6 \times {{10}^{ - 19}}}} = {10^{19}}$
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