MCQ
The number of electrons in the nucleus of ${C^{12}}$ is
- A$6$
- B$12$
- ✓$0$
- D$3$
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$C{H_3}COOH + {H_2}O \rightleftharpoons C{H_3}CO{O^ - } + {H_3}{O^ + }$ is $1.8 \times 10^{-5}$, equilibrium constant for
$C{H_3}COOH + O{H^ - } \rightleftharpoons C{H_3}CO{O^ - } + {H_2}O$
Which of the following arrangements gives the correct order of decreasing stability of the above-mentioned resonance contributors?