MCQ
The number of molecules in $8.96\;L$ of a gas at ${0\,^o}C$ and $1$ atmosphere pressure is approximately
- A$6.02 \times {10^{23}}$
- B$12.04 \times {10^{23}}$
- C$18.06 \times {10^{23}}$
- ✓$24.08 \times {10^{22}}$
$\therefore $ $8.96\,L$ of a gas at $STP$ has no. of molecules $ = \frac{{6.02 \times {{10}^{23}} \times 8.96}}{{22.4}}$
$ = 2.408 \times {10^{23}}$$ = 24.08 \times {10^{22}}$.
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