MCQ
The number of molecules present in $1\, cm^3$ of water is
- A$2.7 \times 10^{19}$
- ✓$3.3 \times 10^{22}$
- C$6.02 \times 10^{20}$
- D$1000$
✓
Answer
Correct option: B.
$3.3 \times 10^{22}$
b
density of water $=1\, \mathrm{g} / \mathrm{mL}$
density of water $=1\, \mathrm{g} / \mathrm{mL}$
$\therefore $ mass of $1\, \mathrm{cm}^{3}$ water $=$ density $\times$ volume
${=1 \times 1}$
${=1\, \mathrm{g}}$
$\therefore $ No. of mole of water molecule in $1 \,\mathrm{cm}^{3}=\frac{1}{18}$
$\therefore $ No. of molecule of $\mathrm{H}_{2} \mathrm{O}$ in $1\, \mathrm{cm}^{3}=\frac{1}{18} \times \mathrm{N}_{\mathrm{A}}$
${=\frac{1}{18} \times 6 \times 10^{23}}$
${=3.3 \times 10^{22}}$
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