MCQ
The number of moles of methane required to produce $11 \mathrm{~g} \mathrm{CO}_2(\mathrm{~g})$ after complete combustion is:
(Given molar mass of methane in $\mathrm{g} \mathrm{mol}^{-1}: 16$ )
- A$0.75$
- ✓$0.25$
- C$0.35$
- D$0.5$
✓
Answer
Correct option: B.
$0.25$
b
$\mathrm{C}_{\mathrm{n}} \mathrm{H}_{2 \mathrm{an} 2}+\frac{3 \mathrm{n}+1}{2} \mathrm{O}_2 \longrightarrow \mathrm{nCO}_2+(\mathrm{n}+1) \mathrm{H}_2 \mathrm{O}$
$\mathrm{C}_{\mathrm{n}} \mathrm{H}_{2 \mathrm{an} 2}+\frac{3 \mathrm{n}+1}{2} \mathrm{O}_2 \longrightarrow \mathrm{nCO}_2+(\mathrm{n}+1) \mathrm{H}_2 \mathrm{O}$
$\underset{4 \mathrm{gm}}{\mathrm{CH}_4+2 \mathrm{O}_2} \longrightarrow \underset{11 \mathrm{gm}}{\mathrm{CO}_2+2 \mathrm{H}_2 \mathrm{O}}$
$0.25 \text { mole } \quad 0.25 \text { mole }$
$\left.0.25 \text { mole } \mathrm{CH}_4 \text { gives } 0.25 \text { mole (or } 11 \mathrm{gm}\right) \mathrm{CO}_2$
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