MCQ
The number of oxygen atoms in $0.2$ mole of sodium carbonate decahydrate is :-
- ✓$1.56 \times 10^{24}$
- B$1.56 \times 10^{23}$
- C$1.56 \times 10^{25}$
- D$3.12 \times 10^{24}$
✓
Answer
Correct option: A.
$1.56 \times 10^{24}$
a
$1$ $mole$ of $\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10 \mathrm{H}_{2} \mathrm{O}$ has $\mathrm{O}$ atoms $=13 \times \mathrm{N}_{\mathrm{A}}$
$1$ $mole$ of $\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10 \mathrm{H}_{2} \mathrm{O}$ has $\mathrm{O}$ atoms $=13 \times \mathrm{N}_{\mathrm{A}}$
$0.2\, \mathrm{mol}$ of $\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10 \mathrm{H}_{2} \mathrm{O}$ has $\mathrm{O}$ atoms
$=0.2 \times 13 \times 6.02 \times 10^{23}=1.56 \times 10^{24}$
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