MCQ
The number of water molecules in $1$ litre of water is
- A$18$
- B$18 \times 1000$
- C${N_A}$
- ✓$55.55\,{N_A}$
Since $ d$ $= 1$
So, $M = V$
$18\,gm = 18\,ml$
$18\,ml$ = $N_A$ molecules ($N_A $= avogadro's no.)
$1000\,ml$ $ = \frac{{{NA}}}{{18}} \times 1000$ = $55.555 \,N_A$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.