MCQ
The number which exceeds its square by the greatest possible quantity is,
- ✓$\frac{1}{2}$
- B$\frac{1}{4}$
- C$\frac{3}{4}$
- DNone of these.
Let the required number be $x.$
Then, $f'(x) = x - x^2$
lmplies that $f(x) = 1 - 2x = 0$
For a local maxima or a local minima, we must have $f'(x) = 0$
lmplies that $2x = 1$
lmplies that $\text{x}=\frac{1}{2}$
Now, $f''(x) = -2 < 0$
Therefore, $\text{x}=\frac{1}{2}$ is a local maxima.
Hence, the required number is $\frac{1}{2}$.
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