MCQ
The oxidation number of chlorine in $\ce{NaClO_3}$ is:
- A$−5$
- B$+2$
- ✓$+5$
- D$−3$
✓
Answer
Correct option: C.
$+5$
The overall charge of molecule is zero $($because it's not an ion$)$. Since sodium is a $1A$ family member, you can assume that the charge is $+1$. The charge of oxygen is almost always $−2$ so you can assume that as well.
$(+1) +$ oxidation of $Cl + 3(−2) = 0$
$(+1) +$ oxidation of $Cl + 3(−2) = 0$
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