MCQ
The oxidation number of sulphur in ${H_2}S{O_4}$ is
- A$-2$
- B$+2$
- C$+4$
- ✓$+6$
$2 + x - 2 \times 4 = 0$, $x = 8 - 2 = + 6$.
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$3MnO_4^{2-} + 2H_2O \rightleftharpoons 2MnO_4^- + MnO_2 + 4OH^-$
The reaction can go to completion by removing $OH^-$ ions by adding