MCQ
The oxidation state of $Cr$ in $Cr_2O_6$ is
- A$-6$
- B$+12$
- ✓$+6$
- D$+4$
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$(I)\,\,C{H_2} = CH - \mathop C\limits^ \oplus {H_2}$
$(II)\,\,C{H_3} - CH_2 - \mathop C\limits^ \oplus {H_2}$
[Assume no volume change on adding $\mathrm{NH}_{3}$ ]
