MCQ
The oxide, which cannot act as a reducing agent, is
  • A
    $N{O_2}$
  • B
    $S{O_2}$
  • $C{O_2}$
  • D
    $Cl{O_2}$

Answer

Correct option: C.
$C{O_2}$
c
(c) Reduction is accompanied by an increase in oxidation number of the reducing agent. $C$ belong to $IVA$ so the max - $O.N.$ is $+4$. In $C{O_2}$ the oxidation number of $C$ is $+4$, which cannot be further increased. Hence, $C{O_2}$ can not act as reducing agent.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free