MCQ
When $0.5\,g$ of sulphur is burnt to $S{O_2},\,4.6\,kJ$ of heat is liberated. What is the enthalpy of formation of sulphur dioxide......$kJ$
- A$+ 147.2 $
- B$-147.2$
- ✓$-294.4$
- D$+ 294.4$
✓
Answer
Correct option: C.
$-294.4$
(c)$S + {O_2} \to S{O_2},\,\,\,\,\Delta {H_f} = - \,4.6\,kJ$
$0.5 $ $gm.$ of sulphur on burning produce $ 1$ $gm$ of $S{O_2}$
$\therefore $ $32 $ $gm$ of sulphur on burning produce $64$ $gm$.. of $S{O_2}$
$\therefore \Delta H = (\, - \,4.6\,kJ\,)\,\, \times 64 = - \,294.4\,kJ$.
$0.5 $ $gm.$ of sulphur on burning produce $ 1$ $gm$ of $S{O_2}$
$\therefore $ $32 $ $gm$ of sulphur on burning produce $64$ $gm$.. of $S{O_2}$
$\therefore \Delta H = (\, - \,4.6\,kJ\,)\,\, \times 64 = - \,294.4\,kJ$.
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