MCQ
The pair of compounds that can exist together is
- A$FeCl_3, SnCl_2$
- B$HgCl_2, SnCl_2$
- ✓$FeCl_2, SnCl_2$
- D$FeCl_3, KI$
✓
Answer
Correct option: C.
$FeCl_2, SnCl_2$
c
The compounds with lower oxidation number and which cannot reduced by one another can exist together. Thus, $F e C l_{2}$ and $S n C l_{2}$ can exist together as $F e^{2+}$ cannot be reduced by $S n^{2+}$
The compounds with lower oxidation number and which cannot reduced by one another can exist together. Thus, $F e C l_{2}$ and $S n C l_{2}$ can exist together as $F e^{2+}$ cannot be reduced by $S n^{2+}$
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