Question
The particle position in one-dimensional motion is
$
x=\left(3+4 t-t^2\right) \text { meter }
$
Draw the displacement velocity diagram for this motion from the time interval $t=0 sec$ to $t=4 sec$.

Answer

Given : $x=\left(3+4 t - t ^2\right)$ meter Differentiation with respect to $t$
$
\begin{aligned}
\frac{d x}{d t} & =0+4 \times 1-2 t \\
\therefore \quad \frac{d x}{d t} & =4-2 t
\end{aligned}
$
Timet01234
Displacementx36763
Velocity$\frac{d x}{d t}$420-2-4
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