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Simple Harmonic Motion — Physics STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 SciencePhysicsSimple Harmonic Motion2 Marks
Question
The pendulum of a clock is replaced by a spring-mass system with the spring having spring constant 0.1N/m. What mass should be attached to the spring?
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Answer

$\text{k}=0.1\text{N/m}$$\text{T}=2\pi\sqrt{\frac{\text{m}}{\text{k}}}=2\sec$ [Time period of pendulum of a clock = 2 sec]
So, $4\pi^{2+}\Big(\frac{\text{m}}{\text{k}}\Big)=4$
$\therefore\text{m}=\frac{\text{k}}{\pi^2}=\frac{0.1}{10}=0.01\text{kg}\approx10\text{gm}.$

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