MCQ
The phase angle between $ e.m.f. $ and current in $ LCR $ series $ ac $ circuit is
- ✓$ 0 $ to $\pi$ $ / 2 $
- B$\pi$ $ / 4$
- C$\pi$ $ / 2$
- D$\pi$
$i=i_0 \sin (\omega t+\phi)$ cument in the circuit
$\phi=$ phase difference between voltage and eument, now
for $L C R$, circuit.
$\left(V_L-V_C\right)=i\left(x_L-x_C\right)$
if $V_L > v_C \Rightarrow 0 < \phi<\pi / 2$
if $v_L < v_c \Rightarrow-\frac{\pi}{2} < \phi < 0$
or $|\phi| \in[0, \pi / 2]$
Hence, option $A$ is correct phase angle between emf and cument is $(0$ to $\pi / 2)$ depending on $v_L$ and $v_C$
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