MCQ
The phase angle between $ e.m.f. $ and current in $ LCR $ series $ ac $  circuit is
  • $ 0 $ to $\pi$ $ / 2 $
  • B
     $\pi$ $ / 4$ 
  • C
     $\pi$ $ / 2$ 
  • D
     $\pi$

Answer

Correct option: A.
$ 0 $ to $\pi$ $ / 2 $
a
Let $V=v_0 \sin (\omega t)$ voltage in cirait

$i=i_0 \sin (\omega t+\phi)$ cument in the circuit

$\phi=$ phase difference between voltage and eument, now

for $L C R$, circuit.

$\left(V_L-V_C\right)=i\left(x_L-x_C\right)$

if $V_L > v_C \Rightarrow 0 < \phi<\pi / 2$

if $v_L < v_c \Rightarrow-\frac{\pi}{2} < \phi < 0$

or $|\phi| \in[0, \pi / 2]$

Hence, option $A$ is correct phase angle between emf and cument is $(0$ to $\pi / 2)$ depending on $v_L$ and $v_C$

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