The plates of a capacitor are charged to potential difference of $V\, volts$ and then connected across a resistor. The potential difference across the capacitor decreases exponentially with respect to time. After one second, the potential difference between the plates is $V/3$; then after two seconds from the start, the potential difference between the plates is
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$\frac{V}{3}=V \cdot e^{-1 / R C}$ or $e^{-1 / R C}=\frac{1}{3}$
$\mathrm{V}^{\prime}=\mathrm{Ve}^{-2 / \mathrm{RC}}=\mathrm{V}\left(\mathrm{e}^{-1 / \mathrm{RC}}\right)^{2}$
$=V\left(\frac{1}{3}\right)^{2}=\frac{V}{9}$
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