$\Delta {U}=\frac{1}{2}({KC}-{C}) {V}^{2}$
$\Delta {U}=\frac{1}{2}(2-1) {CV}^{2}$
$\Delta {U}=\frac{1}{2} \times 200 \times 10^{-6} \times 200 \times 200$
$\Delta {U}=4 {J}$



[take $\ln 5=1.6, \ln 3=1.1]$
Statement $I$ : Electric potential is constant within and at the surface of each conductor.
Statement $II$ : Electric field just outside a charged conductor is perpendicular to the surface of the conductor at every point.
In the light of the above statements, choose the most appropriate answer from the options give below.
