- AGrown junction method
- BAlloying method
- CDiffusion method
- DAll of these
Explanation:
Grown Junction Diode:
Diodes of this type are formed during the crystal pulling process. P and N-type impurities can be alternately added to the molten semiconductor material in the crucible, which results in a P-N junction when crystal is pulled. After slicing, the larger area device can then be cut into a large number of smaller-area semiconductor diodes. Though such diodes, because of larger area, are capable of handling large currents but larger area also introduces more capacitive effects, which are undesirable. Such diodes are used for low frequencies.
Alloy Type or Fused Junction Diode:
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Angle between equipotential surface and lines of force is
|
(a) Zero |
(b) 180° |
(c) 90° |
(d) 45° |
A plane wavefront (λ = 6 falls on a slit 0.4 mm wide. A convex lens of focal length 0.8 m placed behind the slit focusses the light on a screen. What is the linear diameter of second maximum
|
(a) 6mm |
(b) 12 mm |
(c) 3 mm |
(d) 9 mm |
The current inside a copper voltameter
|
(a) Is half the outside value |
(b) Is the same as the outside value |
|
(c) Is twice the outside value |
(d) Depends on the concentration of |
In the adjoining diagram, a wavefront AB, moving in air is incident on a plane glass surface XY. Its position CD after refraction through a glass slab is shown also along with the normals drawn at A and D. The refractive index of glass with respect to air (μ = 1) will be equal to
|
(a) |
(b) |
(c) |
(d) |
Cathode rays enter into a uniform magnetic field perpendicular to the direction of the field. In the magnetic field their path will be
|
(a) Straight line |
(b) Circle |
(c) Parabolic |
(d) Ellipse |
A pendulum bob of mass 30.7 and carrying a charge
is at rest in a horizontal uniform electric field of 20000 V/m. The tension in the thread of the pendulum is (g = 9.8
|
(a) 3 |
(b) 4 |
(c) 5 |
(d) 6 |