MCQ
The point $A$ moves with a uniform speed along the circumference of a circle of radius $0.36\, m$ and covers $30^{\circ}$ in $0.1\, s$. The perpendicular projection $'P'$ from $'A'$ on the diameter $MN$ represents the simple harmonic motion of $'P'.$ The restoration force per unit mass when $P$ touches $M$ will be ...... $N$
  • A
    $100$
  • B
    $0.49$
  • C
    $50$
  • $9.87$

Answer

Correct option: D.
$9.87$
d
$30^{\circ} \rightarrow 0.1\, s$

$360^{\circ} \rightarrow 1.2 \,s = T$

$\omega=\frac{2 \pi}{ T }=\frac{5 \pi}{3}$

At $M , F = m \omega^{2}\, A \Rightarrow \frac{ F }{ m }=\omega^{2}\, A$

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