MCQ
The points $(3a, 0),\, (0, 3b)$ and $(a, 2b)$ are
  • A
    Vertices of an equilateral triangle
  • B
    Vertices of an isosceles triangle
  • C
    Vertices of a right angled isosceles triangle
  • Collinear

Answer

Correct option: D.
Collinear
d
(d) ${l_1} = \sqrt {{{(3a)}^2} + {{(3b)}^2}} = 3\sqrt {{a^2} + {b^2}} $

${l_2} = \sqrt {{a^2} + {b^2}} = \sqrt {{a^2} + {b^2}} $

${l_3} = \sqrt {{{(2a)}^2} + {{(2b)}^2}} = 2\sqrt {{a^2} + {b^2}} $

$ \Rightarrow \,\,{l_1} = {l_2} + {l_3}$

Hence the points are collinear.

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