Question
The potential difference between the two plates of a parallel plate capacitor is constant. When air between the plates is replaced by dielectric material, the electric field intensity:

Answer

Decreases
In general capacitance of parallel plate capacitor is given by:
$\text{C}=\frac{\text{K}\epsilon_0\text{A}}{\text{d}}$
Where $C$ is capacitance $, k$ is relative permittivity of dielectric material $, ϵ_{0​}$ is permittivity of free space constant, $A$ is area of plates and d is distance between them.
Therefore, the capacitance of parallel plates is increased by the insertion of a dielectric material.
Further, the capacitance is inversely proportional to the electric field between the plates, and hence the presence of the dielectric decreases the effective electric field.

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