- AVoltage is less but current is more
- BBoth voltage and current are more
- CVoltage is more but current is less
- DBoth voltage and current are less
Explanation:
The power cables have some resistance.
Power lost in the wires can be calculated as P = I2R with R as the resistance of the wires and I as the current that passes through them.
Power at the load is P = VI.
From this one can see that if voltage is increased by say n times, then only $\frac{1}{\text{n}}$ the current is required to deliver the same power. However, if $\frac{1}{\text{n}}$ current is passed
on the same wires, only $\frac{1}{\text{n}^2}$ of the power will be lost.
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If a torch is used in place of monochromatic light in Young’s experiment what will happens
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(a) Fringe will appear for a moment then it will disappear |
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(b) Fringes will occur as from monochromatic light |
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(c) Only bright fringes will appear |
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(d) No fringes will appear |
The effective resistance between points A and B is
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(a) 10 Ω |
(b) 20 Ω |
|
(c) 40 Ω |
(d) None of the above three values |
Light is an electromagnetic wave. Its speed in vacuum is given by the expression
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(a) |
(b) |
(c) |
(d) |