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Probability — MATHS STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 ScienceMATHSProbability1 Mark
Question
The probability distribution of a discrete random variable $X$ is given below :
$X$0123
$P(X)$$\frac{4}{k}$$\frac{6}{k}$$\frac{4}{k}$$\frac{2}{k}$
The value of $k$ is
✓

Answer

(b) : We have $\Sigma P(X)=1$
$
\Rightarrow \frac{4}{k}+\frac{6}{k}+\frac{4}{k}+\frac{2}{k}=1 \Rightarrow \frac{16}{k}=1 \quad \Rightarrow \quad k=16
$

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