MCQ
The probability that a non-leap year has 53 Sundays, is
  • A
    $\frac{2}{7}$
  • B
    $\frac{5}{7}$
  • C
    $\frac{6}{7}$
  • $\frac{1}{7}$

Answer

Correct option: D.
$\frac{1}{7}$
d

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free