The radius of a charged metal sphere $(R)$ is $10\,cm$ and its potential is $300\,V$. Find the charge density on the surface of the sphere
Medium
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$1$ stat $\mathrm{volt}$ $=300$ $\mathrm{volt}$
$\frac{\mathrm{Q}}{\mathrm{R}}=\frac{\mathrm{Q}}{10}=1$ or $\quad \mathrm{Q}=10$ stat coulomb
$\sigma=\frac{\mathrm{Q}}{4 \pi \mathrm{R}^{2}}=\frac{10}{4 \pi(10)^{2}}=\frac{1}{40 \pi}=8 \times 10^{-3} \mathrm{\,CGS}$ $\mathrm{esu}$
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