Question
The rate constant for a first order reaction is $60~s^{-1}$. How much time will it take to reduce the initial concentration of the reactant to its 1/16th value?
✓
Answer
$t=\frac{2.303}{k} \log \frac{a}{(a-x)}$
if $a=1$ then $(a-x)=1 / 16$
then $\quad t=\frac{2.303}{60} \log \frac{1}{1 / 16}=0.0462 sec$
if $a=1$ then $(a-x)=1 / 16$
then $\quad t=\frac{2.303}{60} \log \frac{1}{1 / 16}=0.0462 sec$
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