$\frac{V_{H_{2}}}{V_{H e}}=\sqrt{\frac{7 / 5}{2} \times \frac{4}{5 / 3}}=\sqrt{\frac{7}{5} \times \frac{4}{2} \times \frac{3}{5}}$
$=\sqrt{\frac{42}{5}}$
$(I)$ a high-pressure pulse starts travelling up the pipe, if the other end of the pipe is open
$(II)$ a low -pressure pulse starts travelling up the pipe, if the other end of the pipe is open
$(III)$ a low pressure pulse starts travelling up the pipe, if the other end of the pipe is closed
$(IV)$ a high-pressure pulse starts travelling up the pipe, if the other end of the pipe is closed