The ratio of Young's modulus of the material of two wires is $2 : 3.$ If the same stress is applied on both, then the ratio of elastic energy per unit volume will be
A$3:2$
B$2:3$
C$3:4$
D$4:3$
Medium
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A$3:2$
a (a) Energy per unit volume $=$ $\frac{{{{({\rm{stress)}}}^{\rm{2}}}}}{{2Y}}$
$\frac{{{E_1}}}{{{E_2}}} = \frac{{{Y_2}}}{{{Y_1}}}$ (Stress is constant)
$\frac{{{E_1}}}{{{E_2}}} = \frac{3}{2}$
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