MCQ
The reaction $CH_{4(g)} + Cl_{2(g)} \to CH_3Cl_{(g)}+ HCl_{(g)}$ has $\Delta H = -25 \,kcal$
$BE(C-Cl) = 84\, kcal, BE \,(H-Cl) = 103\, kcal$
$BE \,(C-H) = X$ and $BE\, (Cl-Cl) = y$
If $\frac{x}{y} = \frac{9}{5}$ then find $y$
  • $70\, kcal$
  • B
    $62 \,kcal$
  • C
    $57.85\, kcal$
  • D
    $80\, cal$

Answer

Correct option: A.
$70\, kcal$
a
$-25=x+y-(84+103)$

$x+y=162$

$\mathrm{x} / \mathrm{y}=\frac{9}{5} \Rightarrow \mathrm{y}=57.85\, \mathrm{kcal}$

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