The reading in the ideal voltmeter $(V)$ shown in the given circuit diagram is :
JEE MAIN 2024, Diffcult
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${i}=\frac{\mathrm{E}_{\text {eq }}}{\mathrm{r}_{\text {eq }}}=\frac{8 \times 5}{8 \times 0.2}$
$I=25 \mathrm{~A}$
$V=E-1 \mathrm{r}$
$=5-0.2 \times 25$
$=0$
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