MCQ
The relationship between force and position is shown in the figure (in one dimensional case). Work done by the force in displacing a body from
X = 1cmto X = 5cmis:

X = 1cmto X = 5cmis:

- A700 ergs
- B70 ergs
- C60 ergs
- D20 ergs

Explanation:
Work is area under the curve.
So In = In1 + In2 + In3 + In4
In1 = arandaundandr A1BCM2
In2 = arandaundandr M2DEF3
In3 = arandaundandr F3GHI4
In4 = arandaundandr I4JKL5
In1 = 10 × 1 = 10ergs
In2 = 20 × 1 = 20ergs
In3 = −20 × 1 = −20ergs
In4 = 10 × 1 = 10ergs
In = In1 + In2 + In3 + In4 = 10 + 20 − 20 + 10 = 20ergs

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