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6.2. Equilibrium - II (icon Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.2. Equilibrium - II (icon Equilibrium)1 Mark
MCQ
The required amount of $KBr$ (molar mass $= 119$ ) in gram to start the precipitation of $AgBr$ in $500\,mL$ solution of $0.05\,M\,\,AgNO_3$ will be :- ( $K_{SP}$ of $AgBr = 5 \times 10^{-13}$ )
  • A
    $1.19\times 10^{-9}\,g$
  • B
    $4\times 10^{-11}\,g$
  • ✓
    $5.95\times 10^{-10}\,g$
  • D
    $2.97\times 10^{-10}\,g$
✓

Answer

Correct option: C.
$5.95\times 10^{-10}\,g$
c

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