The resistance of a galvanometer is $50\, ohms$ and the current required to give full scale deflection is $100\,\mu A$. In order to convert it into an ammeter, reading upto $10\,A$, it is necessary to put a resistance of
AIIMS 1999, Medium
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Resistance in parallel $S = \frac{{G{i_g}}}{{i - {i_g}}} = \frac{{50 \times 100 \times {{10}^{ - 6}}}}{{(10 - 100 \times {{10}^{ - 6}})}}$
$ \Rightarrow $ $S = 5 \times {10^{ - 4}}\,\Omega $
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