[use $m _{p}=1.6 \times 10^{-27} kg , e =1.6 \times 10^{-19} C$ ]
$=\left[\frac{ q ^{2} B ^{2} r _{0}^{2}}{2 m }\right]$
$=18\,MeV$

[use $m _{p}=1.6 \times 10^{-27} kg , e =1.6 \times 10^{-19} C$ ]

Statement $I:$ Biot-Savart's law gives us the expression for the magnetic field strength of an infinitesimal current element (IdI) of a current carrying conductor only.
Statement $II :$ Biot-Savart's law is analogous to Coulomb's inverse square law of charge $q$, with the former being related to the field produced by a scalar source, Idl while the latter being produced by a vector source, $q$. In light of above statements choose the most appropriate answer from the options given below:
