The resistance of an ammeter is $13\, \Omega$ and its scale is graduated for a current upto $100$ $amps$. After an additional shunt has been connected to this ammeter it becomes possible to measure currents upto $750$ $ampere$ by this meter. The value of shunt-resistance is
AIPMT 2007, Medium
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Let the shunt resistance be $S$.
Given: $I=750\, \mathrm{A}$
$I_{\mathrm{g}}=100\, \mathrm{A}, R_{G}=13\, \Omega$
From the figure,
$I_{g} R_{G}=\left(I-I_{g}\right) S$
or $100 \times 13=[750-100] S$
or $1300=650\, S$
$\therefore S=1300 / 650=2\, \Omega$
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