MCQ
The resultant amplitude due to superposition of two waves $y_1 = 5\,\,sin (wt - kx)$ and $y_2 = -5 \,\,cos (wt - kx - 150^o)$
- ✓$5$
- B$5\sqrt 3 $
- C$5\sqrt {2 - \sqrt 3 }$
- D$5\sqrt {2 + \sqrt 3 }$
✓
Answer
Correct option: A.
$5$
a
$y_{1}=5 \sin (\omega t-k x)$
$y_{1}=5 \sin (\omega t-k x)$
$y_{2}=-5 \cos \left(\omega t-k x-150^{\circ}\right)$
$y_{1}+y_{2}=5\left(\sin (\omega t-k x)-\sin \left(\omega t-k x-60^{\circ}\right)\right)$
$=10\left(\sin 30^{\circ} \cos \left(\omega t-k x-30^{\circ}\right)\right)$
$=5 \cos \left(\omega t-k x-30^{\circ}\right)$
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