. . . . . (Given that the value of solubility product of $A B \left( K _{ sp }\right)=2 \times 10^{-10}$ and the value of ionization constant of $H B \left( K _{ a }\right)=1 \times 10^{-8}$ )
$Y \times 10^{-3} =\sqrt{2 \times 10^{-10}\left(1+\frac{10^{-3}}{10^{-8}}\right)}=\sqrt{2 \times 10^{-5}}$
$Y \times 10^{-3} =\sqrt{20 \times 10^{-6}}=\sqrt{20} \times 10^{-3}$
$Y =\sqrt{20}=4.47$
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$\begin{array}{*{20}{c}}
{{H_2}N - CH - CH - CHO} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,} \\
{HOOC\,\,\,\,\,\,\,\,\,\,COOH\,\,\,\,\,}
\end{array}$
| Process | $\Delta H / kJ\,mol ^{-1}$ | $\Delta S / J K^{-1}$ |
| $A$ | $-25$ | $-80$ |
| $B$ | $-22$ | $40$ |
| $C$ | $25$ | $-50$ |
| $D$ | $22$ | $20$ |
The number of non-spontaneous process from the following is $.....$
