MCQ
The solubility of $AgCl$ in $0.2\,\,M\,\,NaCl$ solution $({K_{sp}}$ for $AgCl = 1.20 \times {10^{ - 10}})$ is
- A$0.2\,\,M$
- B$1.2 \times {10^{ - 10}}\,M$
- C$0.2 \times {10^{ - 10}}\,M$
- ✓$6\times {10^{ - 10}}\,M$
✓
Answer
Correct option: D.
$6\times {10^{ - 10}}\,M$
(d) $\mathop {AgCl}\limits_a \rightleftharpoons \mathop {A{g^ + }}\limits_a + \mathop {C{l^ - }}\limits_a $
$\mathop {NaCl}\limits_{0.02} $ $ \rightleftharpoons $ $\mathop {N{a^ + }}\limits_{0.02\,\,\,\,\,} \,\, + \mathop {C{l^ - }}\limits_{0.02\,\,\,\,\,\,} $
${K_{sp}}\,\,AgCl = 1.20 \times {10^{ - 10}}$
${K_{sp}}\,\,AgCl = [A{g^ + }]\,\,[C{l^ - }]$$ = a \times [a + 0.2]$ $ = {a^2} + 0.2a$
${a^2}$ is a very small so it is a neglected.
${K_{sp}}\,\,AgCl = 0.2a$
$1.20 \times {10^{ - 10}} = 0.2a$
$a = \frac{{1.20 \times {{10}^{ - 10}}}}{{0.20}} = 6 \times {10^{ - 10}}$ $mole$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The alkene that will give the same product with $HBr$ in the absence as well as in the presence of peroxide is
→Which of the following is electron rich compound?
Correct order of rate of $EAS$ (electrophilic aromatic substitution) is
→The correct order of increasing energy of atomic orbitals is
With increasing bond order, stability of a bond
The size of nucleus is of the order of
The state of gas can be described by quoting the relationship between,
$0.16\, g$ of dibasic acid required $25 \,ml$ of decinormal $NaOH$ solution for complete neutralisation. The molecular weight of the acid will be
→$6.02 \times 10^{20}$ molecules of urea are present in $100\ mL$ of its solution. The concentration of solution is.....$M$
→Circumference of the first orbit of hydrogen atom is given by the formula :