MCQ
The solubility product of $AB_2$ is $8\times 10^{-5}\,M^3$ . If the salt is $80\,\%$ dissociated in saturated solution, find the solubility of the salt.
Given [Molar mass $(AB_2) = 360$ ]
- A$0.050$
- B$0.065$
- C$0.034$
- ✓$0.074$
Given [Molar mass $(AB_2) = 360$ ]
${{\text{K}}_{{\text{sp}}}} = (0.8 \times {\text{S}}){(2 \times 0.8{\text{S}})^2}$
$8 \times {10^{ - 5}} = 2.048{{\text{S}}^3}\left( { = 2{{\text{S}}^3}} \right)$
${{\text{S}}^3} = \frac{{8 \times {{10}^{ - 5}}}}{2}$
${{\text{S}}^3} = 40 \times {10^{ - 6}}$
$S = \sqrt[3]{{40 \times {{10}^{ - 6}}}}$
$ = 3.4 \times {10^{ - 2}}\,{\text{M}}$
$ = 0.034\,{\text{M}}$
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