- ✓Greater than $7$
- BLess than $7$
- CEqual to $ 7$
- DEqual to zero
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Kaushal's method : $\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}\xrightarrow{{KCl}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
Preeti's method : $C{H_3} - CH = C{H_2}\xrightarrow{{C{l_2} + {H_2}O}}$
Raghav's method : $\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}\xrightarrow[{Pyridine}]{{SOC{l_2}}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$


$F{e^2}+ \left( {aq} \right) + A{g^ + }\left( {aq} \right) \to F{e^{3 + }}\left( {aq} \right) + Ag\left( s \right)$
Given that:
$E_{Ag^+/Ag}^o = xV$
$E_{F{e^{2 + }}/Fe}^o = yV$
$E_{F{e^{3 + }}/Fe}^o = zV$