MCQ
The solution of the $15<\frac{3(\text{x} – 2)}{5}<0$ is:
- A$27 <\times< 2$
- B$27 <\times< -2$
- C$-27 <\times< 2$
- D$27 <\times< -2$
Solution:
Given inequality is:
$15<\frac{3(\text{x} – 2)}{5}<0$
$\Rightarrow15\times5<3(\text{x} – 2)<0 × 5$
$\Rightarrow75<3(\text{x} – 2)<0$
$\Rightarrow\frac{75}{3}<\text{x} – 2<0$
$\Rightarrow25<\text{x}-2<0$
$\Rightarrow25 + 2 <\text{x}<0 + 2$
$\Rightarrow27 <\times< 2$
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